\(\mathrm{Cu^{2+}}\) salt reacts with potassium iodide to give
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- \(\mathrm{Cu_2I_2}\)
- \(\mathrm{Cu_2I_3}\)
- \(\mathrm{CuI}\)
- \(\mathrm{Cu(I_3)_2}\)
The Correct Option is C
Solution and Explanation
\(\mathrm{2Cu^{2+} + 4I^- \rightarrow 2CuI\downarrow + I_2}\)
Options (2) and (4) are not stable compounds because \(\mathrm{Cu^{2+}}\) cannot form \(\mathrm{CuI_2}\) (it oxidises iodide). Option (1) \(\mathrm{Cu_2I_2}\) is only a non-simplest way of writing CuI; the expected answer is the formula CuI, option (3).
Answer: (3) \(\mathrm{CuI}\)
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