Question:

\(\mathrm{[Co_2(CO)_8]}\) displays :

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Apply the 18-electron rule to Co (9 valence electrons) to find the metal-metal bond.
Updated On: Nov 11, 2026
  • one Co-Co bond, six terminal CO and two bridging CO
  • one Co-Co bond, four terminal CO and four bridging CO
  • no Co-Co bond, six terminal CO and two bridging CO
  • no Co-Co bond, four terminal CO and four bridging CO
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The Correct Option is A

Solution and Explanation

Each Co (Z = 27, \(3d^7 4s^2\)) has 9 valence electrons and needs 18 in total.
In the bridged structure each Co has 3 terminal CO (6 e), 2 bridging CO (1 e each from the two bridges, 2 e) and one Co-Co bond (1 e): \(9 + 6 + 2 + 1 = 18\).
Total CO: \(2\times3 = 6\) terminal and 2 bridging = 8.
Answer: (1) one Co-Co bond, six terminal CO and two bridging CO
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