\(\mathrm{A + 2B \rightarrow C}\), the rate equation for this reaction is given as
Rate = k[A][B].
If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself ?
Rate = k[A][B].
If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself ?
Show Hint
- halved
- the same
- doubled
- quadrupled
The Correct Option is C
Solution and Explanation
New rate with \([B]' = 2[B]\) and [A] unchanged: \(r_2 = k[A](2[B]) = 2k[A][B] = 2r_1\).
The rate doubles.
Answer: (3) doubled
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