Question

Match the Xenon compounds in Column-I with its structure in Column II and assign the correct code:

Column I		Column II
A	\(XeF_4\)	I	pyramidall
B	\(XeFe_6 \)	II	square planar
C	\(XeOF_4  \)	III	distorted octahedral
D	\(XeO_3\)	IV	square pyramidal

Code:

• A. (a)-(i) (b)-(ii) (c)-(iii) (d)-(iv)
• B. (a)-(ii) (b)-(iii) (c)-(iv) (d)-(i)
• C. (a)-(ii) (b)-(iii) (c)-(i) (d)-(iv)
• D. (a)-(iii) (b)-(iv) (c)-(i) (d)-(ii)

Answer 1

The Correct Option is B

The question involves matching Xenon compounds with their respective molecular structures. Let's analyze each compound and find suitable matches from the provided options in Column II.

1. Compound \( XeF_4 \): Xenon Tetrafluoride is known to have a sp^3d^2 hybridization. Its structure is square planar with Xenon in the center and four Fluorine atoms at the corners of a square. Thus, the correct match from Column II is II. square planar.
2. Compound \( XeF_6 \): Xenon Hexafluoride has a distorted octahedral structure due to lone pair-bond pair repulsions. It follows sp^3d^3 hybridization. Therefore, this matches with III. distorted octahedral in Column II.
3. Compound \( XeOF_4 \): This compound has a square pyramidal structure, as it contains one Xe=O and four Xe-F bonds with one lone pair on Xenon. This matches up with IV. square pyramidal from Column II.
4. Compound \( XeO_3 \): Xenon Trioxide is characterized by a pyramidal shape due to the presence of three Xe-O bonds and one lone pair on Xenon, making it a pyramidal structure. Hence, this matches with I. pyramidal in Column II.

From the analysis above, the correct matching of Column I with Column II is:

• (a) \( XeF_4 \) - (II) square planar
• (b) \( XeF_6 \) - (III) distorted octahedral
• (c) \( XeOF_4 \) - (IV) square pyramidal
• (d) \( XeO_3 \) - (I) pyramidal

Thus, the correct answer is: (a)-(ii) (b)-(iii) (c)-(iv) (d)-(i).