Question:

Match the type of interaction in column A with the distance dependence of their interaction energy in column B
AB
(i) ion-ion(a) \(\frac{1}{r}\)
(ii) dipole-dipole(b) \(\frac{1}{r^2}\)
(iii) London dispersion(c) \(\frac{1}{r^3}\)
(d) \(\frac{1}{r^6}\)

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Ion-ion energy varies as \(1/r\), fixed dipole-dipole as \(1/r^3\), and London dispersion as \(1/r^6\).
Updated On: Nov 5, 2026
  • (I)-(a), (II)-(b), (III)-(d)
  • (I)-(b), (II)-(d), (III)-(c)
  • (I)-(a), (II)-(b), (III)-(c)
  • (I)-(a), (II)-(c), (III)-(d)
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The Correct Option is D

Solution and Explanation

Interaction energies:
ion-ion (Coulombic): \(E \propto \frac{1}{r}\), so (i)-(a).
dipole-dipole (fixed orientation): \(E \propto \frac{1}{r^3}\), so (ii)-(c). (\(\frac{1}{r^2}\) is for ion-dipole.)
London dispersion: \(E \propto \frac{1}{r^6}\), so (iii)-(d).
This is (I)-(a), (II)-(c), (III)-(d).
Answer: (4) (I)-(a), (II)-(c), (III)-(d)
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