Step 1: Analyzing the first reaction (A).
1-Chloropropane reacts with \( \text{Zn/HCl} \) to undergo a reduction reaction, where the chlorine is replaced by hydrogen. The product of this reaction is propane. This corresponds to R in Column II. Additionally, methanal (formaldehyde) is a side product formed due to the reaction. This corresponds to P in Column II.
Step 2: Analyzing the second reaction (B).
n-Hexane undergoes a Friedel-Crafts alkylation with anhydrous AlCl\(_3\) and HCl, resulting in the formation of propane. This corresponds to Q in Column II.
Step 3: Analyzing the third reaction (C).
2-Methylpropene undergoes oxidation with \( \text{O}_2 \) in the presence of Zn/H\(_2\)O, resulting in the formation of propane. This corresponds to P in Column II.
Step 4: Analyzing the fourth reaction (D).
Propyne reacts with \( \text{HgSO}_4/\text{H}_2\text{SO}_4 \) at 333 K to form 2-Methylpentane and 3-Methylpentane. This corresponds to S in Column II.
Step 5: Conclusion.
After matching the reactions with the correct products, the correct option is (A). Therefore, the correct answer is option (A).