Question:

Match the metals/ions/compounds given in Column-I with the reactions where they act as catalyst as given in Column-II. \[ \begin{array}{llll} (a) & V_2O_5 & (p) & \text{Synthesis of ammonia by Haber's process} \\[6pt] (b) & \text{Fe powder} & (q) & \text{Hydrogenation of alkene} \\[6pt] (c) & Fe^{3+} & (r) & \text{Manufacture of } H_2SO_4 \text{ by Contact Process} \\[6pt] (d) & \text{Ni(s)} & (s) & \text{Oxidation of } I^- \text{ by } S_2O_8^{2-} \end{array} \]

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\[ \begin{aligned} V_2O_5 &: \text{Contact Process} \\ \text{Fe} &: \text{Haber Process} \\ \text{Ni} &: \text{Hydrogenation of alkenes} \\ Fe^{3+} &: \text{Catalyst for } I^- + S_2O_8^{2-} \end{aligned} \]
Updated On: Jun 16, 2026
  • \((a)-(s),\ (b)-(r),\ (c)-(q),\ (d)-(p)\)
  • \((a)-(r),\ (b)-(s),\ (c)-(p),\ (d)-(q)\)
  • \((a)-(s),\ (b)-(q),\ (c)-(r),\ (d)-(p)\)
  • \((a)-(r),\ (b)-(p),\ (c)-(s),\ (d)-(q)\)
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The Correct Option is D

Solution and Explanation

Concept: Specific catalysts are used in industrial and laboratory reactions to increase the rate of reaction without undergoing permanent chemical change.

Step 1: Match the industrial catalysts. Vanadium pentoxide is used in the Contact Process for the manufacture of sulphuric acid. \[ (a)\rightarrow(r) \] Iron powder acts as catalyst in the Haber process for the synthesis of ammonia. \[ (b)\rightarrow(p) \]

Step 2: Match the remaining catalysts. Ferric ion catalyzes the oxidation of iodide ions by persulphate ions. \[ (c)\rightarrow(s) \] Nickel is widely used for catalytic hydrogenation of alkenes. \[ (d)\rightarrow(q) \] \[ \begin{aligned} V_2O_5 &: \text{Contact Process} \\ \text{Fe powder} &: \text{Haber Process} \\ Fe^{3+} &: \text{Oxidation of } I^- \text{ by } S_2O_8^{2-} \\ \text{Ni} &: \text{Hydrogenation of alkenes} \end{aligned} \] Therefore, \[ (a-r),\quad (b-p),\quad (c-s),\quad (d-q) \] \[ \boxed{(a-r),\quad (b-p),\quad (c-s),\quad (d-q)} \] Hence, option \(\mathbf{(D)}\) is correct.
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