Match the LIST-I with LIST-II:

Choose the correct answer from the options given below :
To solve this matching problem, we need to correctly associate each category of molecules (LIST-I) with the appropriate example (LIST-II) based on the octet rule. Let's break down each pair:
Based on the reasoning above, the correct matching is:
A-IV, B-II, C-I, D-III
(A) Molecules obeying octet rule: Molecules like CO2 and CCl4 obey the octet rule, where each atom completes its octet. Hence, A corresponds to IV.
(B) Molecules with incomplete octet: Molecules such as BCl3 and AlCl3 have an incomplete octet on the central atom. Hence, B corresponds to II.
(C) Molecules with incomplete octet with odd electron: NO and NO2 have an odd number of electrons and an incomplete octet. Hence, C corresponds to I.
(D) Molecules with expanded octet: Molecules like H2SO4 and PCl5 have an expanded octet, which means the central atoms have more than eight electrons. Hence, D corresponds to III.
Thus, the correct matching is A-IV, B-II, C-I, D-III.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,