Match the LIST-I with LIST-II:

Choose the correct answer from the options given below :
To solve this matching problem, we need to correctly associate each category of molecules (LIST-I) with the appropriate example (LIST-II) based on the octet rule. Let's break down each pair:
Based on the reasoning above, the correct matching is:
A-IV, B-II, C-I, D-III
(A) Molecules obeying octet rule: Molecules like CO2 and CCl4 obey the octet rule, where each atom completes its octet. Hence, A corresponds to IV.
(B) Molecules with incomplete octet: Molecules such as BCl3 and AlCl3 have an incomplete octet on the central atom. Hence, B corresponds to II.
(C) Molecules with incomplete octet with odd electron: NO and NO2 have an odd number of electrons and an incomplete octet. Hence, C corresponds to I.
(D) Molecules with expanded octet: Molecules like H2SO4 and PCl5 have an expanded octet, which means the central atoms have more than eight electrons. Hence, D corresponds to III.
Thus, the correct matching is A-IV, B-II, C-I, D-III.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)