Reviewing the specific name reactions and their corresponding products is crucial for understanding organic reactions. In these matching-type questions, focus on the reagent and the type of product they generate.
To solve this question, we need to match the reactions from LIST-I to the correct products in LIST-II based on known chemical processes:
Swarts Reaction: This is a halogen exchange reaction where alkyl chlorides or bromides are converted into alkyl fluorides using antimony trifluoride or other metal fluorides. Therefore, the product is Ethyl fluoride (IV).
Sandmeyer’s Reaction: This involves the substitution of an amino group in an aromatic amine with a cyano group using copper(I) cyanide, giving Cyanobenzene (III).
Wurtz Fittig Reaction: This reaction involves the coupling of an aryl halide with an alkyl halide in the presence of sodium metal to form an alkyl-substituted benzene. Therefore, the product formed is Ethyl benzene (I).
Finkelstein Reaction: It is an example of a halogen exchange reaction, where an alkyl chloride or bromide is converted to an iodide using sodium iodide in acetone. Thus, the product is Ethyl iodide (II).
Thus, the correct matching is:
LIST-I
LIST-II
A. Swarts reaction
IV. Ethyl fluoride
B. Sandmeyer's reaction
III. Cyanobenzene
C. Wurtz Fittig reaction
I. Ethyl benzene
D. Finkelstein reaction
II. Ethyl iodide
The correct answer is: A-IV, B-III, C-I, D-II.
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Approach Solution -2
The matching of reactions with their corresponding products is as follows:
A. Swarts reaction:
Produces Ethyl fluoride (IV) through the reaction:
R-Cl/Br + Metal fluoride → R-F
B. Sandmeyer's reaction:
Produces Cyanobenzene (III) through the reaction:
Ar-N2+Cl- + CuCN → Ar-CN
C. Wurtz-Fittig reaction:
Produces Ethyl benzene (I) through the reaction:
Ar-X + R-X + 2Na → Ar-R + 2NaX
D. Finkelstein reaction:
Produces Ethyl iodide (II) through the reaction:
R-Cl/Br + NaI → R-I + NaCl/NaBr
