Match the LIST-I with LIST-II

Choose the correct answer from the options given below:
To match LIST-I with LIST-II, we need to understand the definitions and characteristics of each term:
Based on the analysis above, the correct matching is:
Therefore, the correct option is A-III, B-IV, C-I, D-II.
Correct Matching:
- A: Carbocation - III (sp2 hybridized carbon with empty p-orbital)
- B: C-Free radical - IV (sp2/sp3 hybridized carbon with one unpaired electron)
- C: Nucleophile - I (Species that can supply a pair of electrons)
- D: Electrophile - II (Species that can receive a pair of electrons)
Explanation:
- Carbocations are electron-deficient species with sp2 hybridization and empty p-orbital
- Free radicals have one unpaired electron and can be sp2 or sp3 hybridized
- Nucleophiles are electron-rich species that donate electron pairs
- Electrophiles are electron-deficient species that accept electron pairs
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,