Question

Match the LIST-I with LIST-II 

Choose the correct answer from the options given below:

• A. A-III, B-III, C-I, D-IV
• B. A-III, B-II, C-IV, D-I
• C. A-II, B-III, C-IV, D-I
• D. A-II, B-IV, C-III, D-I

Hint:

- Sodium bicarbonate tests for carboxylic acids via CO\(_2\) evolution - Ferric chloride gives violet color with phenols - Ceric ammonium nitrate turns red with alcohols - Baeyer's reagent (alk. KMnO\(_4\)) tests unsaturation

Answer 1

The Correct Option is C

Matching Analysis:
- A: Sodium bicarbonate solution - Reacts with carboxylic acids (II) to produce effervescence (CO₂)
- B: Neutral ferric chloride - Gives colored complex with phenolic -OH (III)
- C: Ceric ammonium nitrate - Red color with alcoholic -OH (IV)
- D: Alkaline KMnO₄ - Decolorizes with double bonds (I)

Correct Mapping:
- A → II (Carboxylic acid)
- B → III (Phenolic -OH)
- C → IV (Alcoholic -OH)
- D → I (Double bond)