Match the following carboxylic acids with their pKa values.

A-I, B-I, C-III
A-II, B-III, C-I
A-I, B-III, C-II
A-II, B-I, C-III
We are given three carboxylic acids and their corresponding pKa values, and we need to correctly match them.
Step 1: Understanding pKa values
The pKa value of an acid indicates its acidity; lower pKa values correspond to stronger acids.
- Acetic acid (CH$_3$COOH) has a known pKa value of 4.76.
- Benzoic acid (C$_6$H$_5$COOH) has a pKa value of 4.19.
- Trifluoroacetic acid (CF$_3$COOH) is a highly acidic carboxylic acid due to the strong electron-withdrawing effect of fluorine atoms, and its pKa value is 0.23.
Step 2: Matching the values
From the given pKa values, we match:
- \( A \) (CH$_3$COOH) \(\rightarrow\) \( II \) (4.76)
- \( B \) (C$_6$H$_5$COOH) \(\rightarrow\) \( III \) (4.19)
- \( C \) (CF$_3$COOH) \(\rightarrow\) \( I \) (0.23)
Thus, the correct matching is A-II, B-III, C-I, which corresponds to option (2).
| Molisch's lest | Barfoed Test | Biuret Test | |
|---|---|---|---|
| A | Positive | Negative | Negativde |
| B | Positive | Positive | Negative |
| C | Negative | Negative | Positive |
The \( \Delta_f H^\theta \) of \( AO_3(s) \), \( BO_2(s) \), and \( ABO_3(s) \) is -635, \( x \), and -1210 kJ mol\(^{-1}\) respectively. The reaction:
\( ABO_3 (s) \rightarrow AO_3 (s) + BO_2 (g) \)
Has an enthalpy change of \( \Delta_r H^\theta = 175 \) kJ mol\(^{-1}\). What is the value of \( x \) (in kJ mol\(^{-1}\))?
At 27°C, 100 mL of 0.5 M HCl is mixed with 100 mL of 0.4 M NaOH solution. To this resultant solution, 800 mL of distilled water is added. What is the pH of the final solution?
The bromides formed by the cleavage of ethers A and B with HBr respectively are:
