Question

Match the following \[ \begin{array}{|c|l|c|l|} \hline & List-I & & List-II \hline A & \text{Microfiltration} & I & \text{Removal of salts} B & \text{Ultrafiltration} & II & \text{Protein concentration} C & \text{Reverse osmosis} & III & \text{Suspended solids/bacteria} D & \text{Dialysis} & IV & \text{Small solute diffusion} \hline \end{array} \] The correct matching is

• A. A -- III, B -- II, C -- I, D -- IV
• B. A -- II, B -- III, C -- IV, D -- I
• C. A -- I, B -- IV, C -- III, D -- II
• D. A -- IV, B -- I, C -- II, D -- III

Hint:

Membrane separation techniques: \[ \boxed{ \begin{aligned} \text{Microfiltration} &\rightarrow \text{Cells, bacteria} \text{Ultrafiltration} &\rightarrow \text{Proteins} \text{Reverse osmosis} &\rightarrow \text{Salts} \text{Dialysis} &\rightarrow \text{Small molecules} \end{aligned} } \]

Answer 1

The Correct Option is A

Step 1: Recall the applications of membrane separation techniques. \[ \boxed{ \begin{aligned} \text{Microfiltration} &\rightarrow \text{Removes suspended solids and bacteria} \text{Ultrafiltration} &\rightarrow \text{Concentrates proteins} \text{Reverse osmosis} &\rightarrow \text{Removes dissolved salts} \text{Dialysis} &\rightarrow \text{Removes small solutes by diffusion} \end{aligned} } \]

Step 2: Match List-I with List-II. Thus, \[ \boxed{ A-\mathrm{III},\; B-\mathrm{II},\; C-\mathrm{I},\; D-\mathrm{IV} } \] Therefore, \[ \boxed{(A)} \] is the correct answer.