Concept:
The iron-carbon system contains important phases that define the mechanical behavior of steels. Each phase has a distinct crystal structure and carbon solubility.
Step 1: Identify Austenite.
Austenite:
• FCC phase of iron
• stable at high temperature
• high carbon solubility
Thus:
\[
A \rightarrow II
\]
Step 2: Identify Ferrite.
Ferrite:
• BCC phase of iron
• soft and ductile
• low carbon solubility
Thus:
\[
B \rightarrow I
\]
Step 3: Identify Cementite.
Cementite:
• iron carbide (Fe$_3$C)
• hard and brittle phase
Thus:
\[
C \rightarrow IV
\]
Step 4: Identify Pearlite.
Pearlite:
• lamellar mixture of ferrite + cementite
• formed by eutectoid reaction
Thus:
\[
D \rightarrow III
\]
Final Answer:
\[
\boxed{A-II,\; B-I,\; C-IV,\; D-III}
\]