Question:

Match the following:

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Pearlite = alternating layers of ferrite and cementite.
Updated On: Jun 29, 2026
  • A-I, B-III, C-IV, D-II
  • A-II, B-I, C-IV, D-III
  • A-IV, B-I, C-II, D-III
  • A-III, B-II, C-I, D-IV
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The Correct Option is B

Solution and Explanation

Concept: The iron-carbon system contains important phases that define the mechanical behavior of steels. Each phase has a distinct crystal structure and carbon solubility.

Step 1:
Identify Austenite.
Austenite:
• FCC phase of iron
• stable at high temperature
• high carbon solubility Thus: \[ A \rightarrow II \]

Step 2:
Identify Ferrite.
Ferrite:
• BCC phase of iron
• soft and ductile
• low carbon solubility Thus: \[ B \rightarrow I \]

Step 3:
Identify Cementite.
Cementite:
• iron carbide (Fe$_3$C)
• hard and brittle phase Thus: \[ C \rightarrow IV \]

Step 4:
Identify Pearlite.
Pearlite:
• lamellar mixture of ferrite + cementite
• formed by eutectoid reaction Thus: \[ D \rightarrow III \] Final Answer: \[ \boxed{A-II,\; B-I,\; C-IV,\; D-III} \]
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