Question

Match the following

• A. (i)-(A), (ii)-(D), (iii)-(B), (iv)-(C)
• B. (i)-(B), (ii)-(C), (iii)-(D), (iv)-(A)
• C. (i)-(A), (ii)-(B), (iii)-(C), (iv)-(D)
• D. (i)-(D), (ii)-(A), (iii)-(B), (iv)-(C)

Hint:

Remember key reagents: Finkelstein uses NaI/acetone, Swarts uses fluorinating agents like SbF$_3$, Wurtz uses Na/dry ether, and Sandmeyer uses cuprous salts for substitution of diazonium salts.

Answer 1

The Correct Option is A

Step 1: Identify Finkelstein reaction.
Finkelstein reaction is a halogen exchange reaction in which alkyl chlorides or bromides react with sodium iodide in acetone to form alkyl iodides.
\[ \mathrm{R-Cl + NaI \rightarrow R-I + NaCl} \] Hence, Finkelstein reaction corresponds to NaI / Acetone (A).
Step 2: Identify Swarts reaction.
Swarts reaction is used to prepare alkyl fluorides from alkyl chlorides or bromides using metallic fluorides such as SbF$_3$.
Thus, Swarts reaction corresponds to SbF$_3$ (D).
Step 3: Identify Wurtz reaction.
Wurtz reaction involves coupling of alkyl halides using sodium metal in dry ether to form higher alkanes.
\[ \mathrm{2R-X + 2Na \rightarrow R-R + 2NaX} \] Thus, Wurtz reaction corresponds to Na / Dry Ether (B).
Step 4: Identify Sandmeyer reaction.
Sandmeyer reaction involves the substitution of diazonium salts using cuprous salts such as Cu$_2$Cl$_2$ in the presence of HCl to form aryl halides.
Thus, Sandmeyer reaction corresponds to Cu$_2$Cl$_2$ / HCl (C).
Step 5: Final matching.
\[ (i)-(A), \quad (ii)-(D), \quad (iii)-(B), \quad (iv)-(C) \] Final Answer: (A) (i)-(A), (ii)-(D), (iii)-(B), (iv)-(C)