Match List-I with the List-IIList-I
(Precipitating reagent and
conditions) List-II
(Cation) (A) \(NH_4Cl + NH_4OH\) (I) Mn2+ (B) \(NH_4OH + Na_2CO_3\) (II) Pb2+ (C) \(NH_4OH + NH_4Cl + H_2S gas\) (III) Al3+ (D) dilute HCl (IV) Sr2+
Choose the correct answer from the options given below:
| List-I (Precipitating reagent and conditions) | List-II (Cation) |
|---|---|
| (A) \(NH_4Cl + NH_4OH\) | (I) Mn2+ |
| (B) \(NH_4OH + Na_2CO_3\) | (II) Pb2+ |
| (C) \(NH_4OH + NH_4Cl + H_2S gas\) | (III) Al3+ |
| (D) dilute HCl | (IV) Sr2+ |
- A-IV, B-III, C-II, D-I
- A-IV, B-III, C-I, D-II
- A-III, B-IV, C-I, D-II
- A-III, B-IV, C-II, D-I
The Correct Option is C
Approach Solution - 1
To solve the given problem, we need to match the reagents and conditions from List-I with the corresponding cations from List-II. Each reagent precipitates specific cations under given conditions:
- (A) \(NH_4Cl + NH_4OH\):
- This combination is commonly used to precipitate aluminum hydroxide, \(Al(OH)_3\), from solutions containing \(Al^{3+}\) ions.
- (B) \(NH_4OH + Na_2CO_3\):
- This combination is effective in precipitating carbonates of alkaline earth metals like strontium carbonate, \(SrCO_3\), thus it is associated with \(Sr^{2+}\).
- (C) \(NH_4OH + NH_4Cl + H_2S\) gas:
- In an alkaline medium provided by \(NH_4OH\) and \((NH_4)_2S\), sulfides of certain cations such as \(MnS\) can be precipitated. Here, it matches with \(Mn^{2+}\).
- (D) Dilute HCl:
- This is often used to precipitate chlorides of certain metal ions such as \(PbCl_2\). Therefore, it matches with \(Pb^{2+}\).
Based on the information above, the correct matching is:
- (A) \(NH_4Cl + NH_4OH\) matches \(Al^{3+}\) so it is III.
- (B) \(NH_4OH + Na_2CO_3\) matches \(Sr^{2+}\) so it is IV.
- (C) \(NH_4OH + NH_4Cl + H_2S\) gas matches \(Mn^{2+}\) so it is I.
- (D) Dilute HCl matches \(Pb^{2+}\) so it is II.
The correct option is A-III, B-IV, C-I, D-II.
Approach Solution -2
The matching is based on the chemical properties and specific precipitation conditions for cations:
[A.] NH$_4$Cl + NH$_4$OH precipitates Al(OH)$_3$, hence matches with III. Al$^{3+}$.
[B.] NH$_4$OH + Na$_2$CO$_3$ precipitates SrCO$_3$, hence matches with IV. Sr$^{2+}$.
[C.] NH$_4$OH + NH$_4$Cl + H$_2$S gas precipitates PbS, hence matches with II. Pb$^{2+}$.
[D.] Dilute HCl precipitates MnCl$_2$, hence matches with I. Mn$^{2+}$.
Thus, the correct order is:
\[A -- III, B -- IV, C -- II, D -- I.\]
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