
To solve this matching question, we need to identify the common uses of each compound listed in List-I by matching them correctly with List-II.
Based on the analysis, the correct match of List-I with List-II is:
Therefore, the correct answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II).
Matching Explanation: -
(A) Carbon tetrachloride: Used as a fire extinguisher in the past due to its non-flammable properties. Hence, it matches with (III).
(B) Methylene chloride: Commonly used as a paint remover due to its ability to dissolve paint and coatings. Hence, it matches with (I).
(C) DDT: Known for its use as a non-biodegradable insecticide, which has been widely restricted due to environmental concerns. Hence, it matches with (IV).
(D) Freons: These are used as refrigerants and in air conditioners due to their heat absorption and transfer properties. Hence, it matches with (II).
Conclusion: The correct matching is:
• (A)-(III)
• (B)-(I)
• (C)-(IV)
• (D)-(II)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| List I (Substances) | List II (Element Present) |
| (A) Ziegler catalyst | (I) Rhodium |
| (B) Blood Pigment | (II) Cobalt |
| (C) Wilkinson catalyst | (III) Iron |
| (D) Vitamin B12 | (IV) Titanium |
| List-I (Complex ion) | List-II (Spin only magnetic moment in B.M.) |
|---|---|
| (A) [Cr(NH$_3$)$_6$]$^{3+}$ | (I) 4.90 |
| (B) [NiCl$_4$]$^{2-}$ | (II) 3.87 |
| (C) [CoF$_6$]$^{3-}$ | (III) 0.0 |
| (D) [Ni(CN)$_4$]$^{2-}$ | (IV) 2.83 |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)