Question:
Match list I with list II:
List I Species List II Geometry/ Shape A H3 O+ I Tetrahedral B Acetylide anion II Linera C NH4 + III Pyramidal D ClO2– IV Bent
Choose correct answer from the options given below:
Match list I with list II:
Choose correct answer from the options given below:
| List I | Species | List II | Geometry/ Shape |
| A | H3 O+ | I | Tetrahedral |
| B | Acetylide anion | II | Linera |
| C | NH4 + | III | Pyramidal |
| D | ClO2– | IV | Bent |
Choose correct answer from the options given below:
Show Hint
Remember that the geometry of molecules is determined by the number of bonding pairs and lone pairs on the central atom, according to the VSEPR theory.
Updated On: Mar 26, 2026
- A-I, B-II, C-III, D-IV
- A-IV, B-I, C-III, D-II
- A-II, B-IV, C-I, D-III
- A-III, B-II, C-IV, D-I
Show Solution
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The Correct Option is A
Solution and Explanation
- A. H\(_2\)O: Water has a bent shape due to the lone pairs on oxygen, making the geometry bent.
- B. Acetylene: Acetylene is a linear molecule with a triple bond between the carbons.
- C. NH\(_3\): Ammonia has a trigonal pyramidal shape due to the lone pair on nitrogen.
- D. ClO\(_2\): Chlorine dioxide is a bent molecule due to the lone pairs on chlorine.
Thus, the correct matching is A-I, B-II, C-III, D-IV.
- B. Acetylene: Acetylene is a linear molecule with a triple bond between the carbons.
- C. NH\(_3\): Ammonia has a trigonal pyramidal shape due to the lone pair on nitrogen.
- D. ClO\(_2\): Chlorine dioxide is a bent molecule due to the lone pairs on chlorine.
Thus, the correct matching is A-I, B-II, C-III, D-IV.
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