Match List I with List II
| List I | List II | ||
| A | ![]() | I | Fittig reaction |
| B | ![]() | II | Wurtz Fittig reaction |
| C | ![]() | III | Finkelstein reaction |
| D | \(C_{2}H_{5}CI + NaI \rightarrow C_{2}H_{5}I + NaCl\) | IV | Sandmeyer reaction |
Choose the correct answer from the options given below:
kk
So, the correct answer is (B): A - II, B - I, C - IV, D - III

Match the LIST-I with LIST-II: 
Choose the correct answer from the options given below:
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :

The hydrocarbons such as Haloalkanes and Haloarenes are the ones, in which one or more hydrogen atoms are replaced with halogen atoms. The main difference between Haloalkanes and Haloarenes is that Haloalkanes are derived from open chained hydrocarbons, also called alkanes, and Haloarenes are derived from aromatic hydrocarbons.