Question:

Match List - I with List - II.
List - IList - II
(A)\(\mathrm{C_6H_5COCl}\ \xrightarrow{\mathrm{H_2,\ Pd\text{-}BaSO_4}}\ \mathrm{C_6H_5CHO}\) [structures drawn in the paper](I)Gatterman Koch reaction
(B)\(\mathrm{CH_3-CN}\ \xrightarrow[\mathrm{H_3O^+}]{\mathrm{SnCl_2/HCl}}\ \mathrm{CH_3-CHO}\)(II)Etard reaction
(C)\(\mathrm{C_6H_5CH_3}\ \xrightarrow[\mathrm{H_3O^+}]{\mathrm{CrO_2Cl_2}}\ \mathrm{C_6H_5CHO}\) [structures drawn in the paper](III)Stephen reaction
(D)\(\mathrm{C_6H_6}\ \xrightarrow[\mathrm{AlCl_3\ (anhyd)}]{\mathrm{CO,\ HCl}}\ \mathrm{C_6H_5CHO}\) [structures drawn in the paper](IV)Rosenmund reaction
Choose the correct answer from the options given below :

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Identify each named reaction: acid chloride to aldehyde (Rosenmund), nitrile to aldehyde with SnCl2/HCl (Stephen), toluene with CrO2Cl2 (Etard), benzene with CO/HCl/AlCl3 (Gatterman-Koch).
Updated On: Nov 4, 2026
  • \((\mathrm{A})-(\mathrm{IV}),\ (\mathrm{B})-(\mathrm{III}),\ (\mathrm{C})-(\mathrm{II}),\ (\mathrm{D})-(\mathrm{I})\)
  • \((\mathrm{A})-(\mathrm{I}),\ (\mathrm{B})-(\mathrm{II}),\ (\mathrm{C})-(\mathrm{III}),\ (\mathrm{D})-(\mathrm{IV})\)
  • \((\mathrm{A})-(\mathrm{II}),\ (\mathrm{B})-(\mathrm{III}),\ (\mathrm{C})-(\mathrm{IV}),\ (\mathrm{D})-(\mathrm{I})\)
  • \((\mathrm{A})-(\mathrm{III}),\ (\mathrm{B})-(\mathrm{II}),\ (\mathrm{C})-(\mathrm{I}),\ (\mathrm{D})-(\mathrm{IV})\)
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The Correct Option is A

Solution and Explanation

(A) Benzoyl chloride is reduced to benzaldehyde by \(\mathrm{H_2}\) over poisoned \(\mathrm{Pd/BaSO_4}\): this is the Rosenmund reduction, (IV).
(B) Nitrile reduced with \(\mathrm{SnCl_2/HCl}\) to an imine hydrochloride, which hydrolyses with \(\mathrm{H_3O^+}\) to the aldehyde: Stephen reaction, (III).
(C) Toluene oxidised by chromyl chloride \(\mathrm{CrO_2Cl_2}\) (in \(\mathrm{CS_2}\)) to a chromium complex, which on hydrolysis gives benzaldehyde: Etard reaction, (II).
(D) Benzene formylated with \(\mathrm{CO}\) + HCl in presence of anhydrous \(\mathrm{AlCl_3}\): Gatterman-Koch reaction, (I).
So (A)-(IV), (B)-(III), (C)-(II), (D)-(I), which is option (1).
Answer: (1) (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
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