Question:
Match List I with List II List I List II A \(2^{n+1}\) I ω(n) B \(2^{2n}\) II 0(2n) C \(2^\frac{n}{2}{}\) III ω(2n) D \(n^n\) IV 0(2n)
Match List I with List II
| List I | List II | ||
| A | \(2^{n+1}\) | I | ω(n) |
| B | \(2^{2n}\) | II | 0(2n) |
| C | \(2^\frac{n}{2}{}\) | III | ω(2n) |
| D | \(n^n\) | IV | 0(2n) |
Updated On: Mar 16, 2024
- A-I, B-III, C-IV, D-II
- A-II, B-III, C-IV, D-I
- A-1, B-II, C-III, D-IV
- A-IV, B-III, C-II, D-I
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The Correct Option is D
Solution and Explanation
The correct option is(D): A-IV, B-III, C-II, D-I
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