Match List - I with List - II:
List - I:
(A) \( {[MnBr}_4]^{2-} \)
(B) \( {[FeF}_6]^{3-} \)
(C) \( {[Co(C}_2{O}_4)_3]^{3-} \)
(D) \( [Ni(CO)_4] \)
List - II:
(I) \( d^2sp^3 \) & diamagnetic
(II) \( sp^2d^2 \) & paramagnetic
(III) \( sp^3 \) & diamagnetic
(IV) \( sp^3 \) & paramagnetic
Choose the correct answer from the options given below:
(B) \( {[FeF}_6]^{3-} \)
(C) \( {[Co(C}_2{O}_4)_3]^{3-} \)
(D) \( [Ni(CO)_4] \)
List - II: (I) \( d^2sp^3 \) & diamagnetic
(II) \( sp^2d^2 \) & paramagnetic
(III) \( sp^3 \) & diamagnetic
(IV) \( sp^3 \) & paramagnetic
Choose the correct answer from the options given below:
Show Hint
- \( {(A)-(III)}, {(B)-(II)}, {(C)-(I)}, {(D)-(IV)} \)
- \( {(A)-(IV)}, {(B)-(I)}, {(C)-(II)}, {(D)-(III)} \)
- \( {(A)-(I)}, {(B)-(II)}, {(C)-(III)}, {(D)-(IV)} \)
- \( {(A)-(IV)}, {(B)-(I)}, {(C)-(III)}, {(D)-(II)} \)
The Correct Option is A
Solution and Explanation
- A) \( {[MnBr}_4]^{2-} \): The \( {Mn}^{2+} \) ion has an \( 3d^5 \) configuration, leading to an \( sp^3 \) hybridization with a diamagnetic behavior due to the pairing of electrons. Hence, it corresponds to (III).
- B) \( {[FeF}_6]^{3-} \): The \( {Fe}^{3+} \) ion has a \( 3d^5 \) configuration, resulting in \( sp^2d^2 \) hybridization with paramagnetic behavior. Hence, it corresponds to (II).
- C) \( {[Co(C}_2{O}_4)_3]^{3-} \): The \( {Co}^{3+} \) ion leads to a \( 3d^6 \) configuration, requiring \( d^2sp^3 \) hybridization with diamagnetic behavior. Hence, it corresponds to (I).
- D) \( [Ni(CO)_4] \): The \( {Ni}^{2+} \) ion has a \( 3d^8 \) configuration with \( sp^3 \) hybridization and paramagnetic behavior. Hence, it corresponds to (IV). Thus, the correct matching is (A)-(III), (B)-(II), (C)-(I), (D)-(IV).
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