Match List - I with List - II.
Choose the correct answer from the options given below :
Choose the correct answer from the options given below :
Show Hint
- (a) \(\to\) (ii), (b) \(\to\) (iv), (c) \(\to\) (i), (d) \(\to\) (iii)
- (a) \(\to\) (iii), (b) \(\to\) (iv), (c) \(\to\) (i), (d) \(\to\) (ii)
- (a) \(\to\) (iii), (b) \(\to\) (i), (c) \(\to\) (iv), (d) \(\to\) (ii)
- (a) \(\to\) (ii), (b) \(\to\) (i), (c) \(\to\) (iv), (d) \(\to\) (iii)
The Correct Option is A
Solution and Explanation
(b) Benzenediazonium chloride with Cu/HCl gives chlorobenzene + \(\mathrm{N_2}\): Gattermann reaction, (iv).
(c) \(\mathrm{2CH_3CH_2Cl + 2Na \to C_2H_5-C_2H_5 + 2NaCl}\) (coupling of alkyl halides in dry ether): Wurtz reaction, (i).
(d) \(\mathrm{2C_6H_5Cl + 2Na \to C_6H_5-C_6H_5 + 2NaCl}\) (coupling of aryl halides): Fittig reaction, (iii).
Thus (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii).
Answer: (1) (a) \(\to\) (ii), (b) \(\to\) (iv), (c) \(\to\) (i), (d) \(\to\) (iii)
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