Question

Match List-I with List-II. 

List-I	Molecule
A	C₂H₄
B	C₂H₂
C	CH₄
D	NH₃

 

List-II	Bonding feature
I	1σ bond, 2π bonds
II	3σ bonds, 1 lone pair
III	4σ bonds
IV	1σ bond, 1π bond

• A. A-I, B-II, C-IV, D-III
• B. A-III, B-IV, C-II, D-I
• C. A-II, B-IV, C-I, D-III
• D. A-IV, B-I, C-III, D-II

Hint:

Single bond \(=1\sigma\), double bond \(=1\sigma+1\pi\), and triple bond \(=1\sigma+2\pi\).

Answer 1

The Correct Option is D

Step 1: Bonding in \(C_2H_4\).
Ethene contains a carbon-carbon double bond: \[ C=C. \] A double bond consists of: \[ 1\sigma+1\pi. \] So: \[ A-IV. \]

Step 2: Bonding in \(C_2H_2\).
Ethyne contains a carbon-carbon triple bond: \[ C\equiv C. \] A triple bond consists of: \[ 1\sigma+2\pi. \] So: \[ B-I. \]

Step 3: Bonding in \(CH_4\).
Methane has four C--H single bonds. Each single bond is a sigma bond. So methane contains: \[ 4\sigma \text{ bonds}. \] Therefore: \[ C-III. \]

Step 4: Bonding in \(NH_3\).
Ammonia has: \[ 3 \] N--H sigma bonds and one lone pair on nitrogen. So: \[ D-II. \] Therefore, the correct matching is: \[ A-IV,\quad B-I,\quad C-III,\quad D-II. \]