Match List I with List II. List I (Anion) List II (gas evolved on reaction with dil \(H_2SO_4\)) A. \(CO_3^{ 2−}\) I. Colourless gas which turns lead acetate paper black. B. \(S^{2–}\) II. Colourless gas which turns acidified potassium dichromate solution green C. \(SO_3^{ 2−}\) III. Brown fumes which turns acidified KI solution containing starch blue. D. \(NO_2^{−}\) IV. Colourless gas evolved with brisk effervescence, which turns lime water milky.
Choose the correct answer from the options given below:
| List I (Anion) | List II (gas evolved on reaction with dil \(H_2SO_4\)) | ||
|---|---|---|---|
| A. | \(CO_3^{ 2−}\) | I. | Colourless gas which turns lead acetate paper black. |
| B. | \(S^{2–}\) | II. | Colourless gas which turns acidified potassium dichromate solution green |
| C. | \(SO_3^{ 2−}\) | III. | Brown fumes which turns acidified KI solution containing starch blue. |
| D. | \(NO_2^{−}\) | IV. | Colourless gas evolved with brisk effervescence, which turns lime water milky. |
- A-III, B-I, C-II, D-IV
- A-II, B-I, C-IV, D-III
- A-IV, B-I, C-III, D-II
- A-IV, B-I, C-II, D-III
The Correct Option is D
Solution and Explanation
\(CO_3^{ 2−}\): On action of diluted sulphuric acid, \(CO_2\) gas is released which turns lime water milky.
\(S ^{2-}:\) On action of diluted sulphuric acid, \(H_2S\) gas is released which turns lead acetate paper black.
\(SO_3^{ 2−}\): On action of diluted \( H_2SO_4, SO_2\) gas is evolved which turns acidified potassium dichromate solution green.
\(NO^{2−}\): On action of dil \(H_2SO_4, NO_2\) gas is evolved which turns Kl solution contain starch blue.
\(Hence,\) the correct option is (D): \(A-IV, B-I, C-II, D-III\)
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main Gas laws Questions
- If \(5\) moles of an ideal gas expands from \(10\) L to a volume of \(100\) L at \(300k\) under isothermal and reversible condition then work, \(W\), is \(- x J\). The value of x is \((even \;n = 8.314 \;J \;K^{-1} mol^{-1})\)
- Rms velocity of hydrogen at which temperature is equal to that of the oxygen molecule at \(47 \degree\)
0.05 cm thick coating of silver is deposited on a plate of 0.05 m2 area. The number of silver atoms deposited on plate are _____ × 1023. (At mass Ag = 108,d = 7.9 g/cm³)
- Amount of magnesium (Mg) (in mg) required to liberate 224 mL of \( H_2 \) gas at STP, when reacted with HCl.
- Statement 1: Hyper conjugation is not a permanent effect Statement 2: In general, greater the number of Alkyl groups attached to a positively charged carbon atom, greater is the Hyper conjugation interaction and stabilization of the cation.
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
Concepts Used:
Gas Laws
The gas laws were developed at the end of the 18th century, when scientists began to realize that relationships between pressure, volume and temperature of a sample of gas could be obtained which would hold to approximation for all gases.
The five gas laws are:
- Boyle’s Law, which provides a relationship between the pressure and the volume of a gas.
- Charles’s Law, which provides a relationship between the volume occupied by a gas and the absolute temperature.
- Gay-Lussac’s Law, which provides a relationship between the pressure exerted by a gas on the walls of its container and the absolute temperature associated with the gas.
- Avogadro’s Law, which provides a relationship between the volume occupied by a gas and the amount of gaseous substance.
- The Combined Gas Law (or the Ideal Gas Law), which can be obtained by combining the four laws listed above.