Question

Match List I with List II and select the correct options

Codes:

• A. a – iv, b – i, c – ii, d – iii
• B. a - iii, b - ii, c - iv, d - i
• C. a – iii, b – ii, c – i, d – iv
• D. a – ii, b – iii, c – iv, d - i

Hint:

It is essential to memorize the common functional group tests in organic chemistry.

• \textbf{Phenols}: Neutral FeCl\(_3\) test (violet color).
• \textbf{Aldehydes}: Tollen's test (silver mirror) or Fehling's test (red ppt).
• \textbf{Alcohols}: Ceric Ammonium Nitrate (red color) or Lucas test (turbidity for 1\(^\circ\), 2\(^\circ\), 3\(^\circ\)).
• \textbf{Primary Aromatic Amines}: Azo dye test (colored dye).

Answer 1

The Correct Option is B

Step 1: Match each functional group with its characteristic test.
(a) Secondary Alcohol (e.g., propan-2-ol shown in the image): Alcohols give a positive test with Ceric Ammonium Nitrate (CAN). The solution turns from yellow to red. So, a \(\rightarrow\) iii.
(b) C\(_6\)H\(_5\)NH\(_2\) (Aniline, a primary aromatic amine): Primary aromatic amines undergo a diazotization reaction (with NaNO\(_2\)/HCl at 0\(^\circ\)C) followed by coupling with a phenol (like \(\beta\)-naphthol) to form a brightly colored azo dye (orange-red precipitate). This is the basis of the azo dye test. So, b \(\rightarrow\) ii.
(c) CH\(_3\)CH\(_2\)CHO (Propanal, an aldehyde): Aldehydes are readily oxidized and give a positive test with Tollen's reagent (ammoniacal silver nitrate solution). They reduce Ag\(^+\) ions to metallic silver, forming a silver mirror on the inside of the test tube. So, c \(\rightarrow\) iv.
(d) Phenol: Phenols have a weakly acidic hydroxyl group directly attached to a benzene ring. They give a characteristic coloration (usually violet, but can be blue or green) with a neutral ferric chloride (FeCl\(_3\)) solution due to the formation of a colored iron-phenoxide complex. So, d \(\rightarrow\) i.
Step 2: Compile the matches.
The correct matches are:

• a \(\rightarrow\) iii
• b \(\rightarrow\) ii
• c \(\rightarrow\) iv
• d \(\rightarrow\) i

Step 3: Final Answer.
This combination corresponds to option (B).