Question:

Match List I (Disease) with List II (Vector) and select the correct answer using the codes given below the lists.

List I (Disease)List II (Vector)
A. Scabies1. Soft tick
B. Fish tapeworm infestation2. Cyclops
C. Relapsing fever3. Sarcoptes
D. Kyasanur Forest disease4. Hard tick

Show Hint

Think of each disease's actual biological carrier: a mite, a water flea, a soft tick, or a hard tick.
Updated On: Jul 7, 2026
  • A-3, B-2, C-1, D-4
  • A-4, B-1, C-2, D-3
  • A-3, B-1, C-2, D-4
  • A-4, B-2, C-1, D-3
Show Solution
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The Correct Option is A

Solution and Explanation

Step 1: Match Scabies with its vector.
Scabies is caused by the mite Sarcoptes scabiei, which burrows into the skin and causes the itching and burrow lines seen in this disease. Here the mite itself acts as the causative and transmitting agent, so Scabies pairs with Sarcoptes, item 3.

Step 2: Match Fish tapeworm infestation with its vector.
Fish tapeworm, Diphyllobothrium latum, needs two intermediate hosts to complete its life cycle. The first intermediate host is a small water flea called Cyclops, which carries the larval stage before it is eaten by fish. So Fish tapeworm infestation pairs with Cyclops, item 2.

Step 3: Match Relapsing fever with its vector.
Relapsing fever is caused by Borrelia species. The endemic, tick borne form spreads through the bite of the soft tick, genus Ornithodoros. So Relapsing fever pairs with Soft tick, item 1.

Step 4: Match Kyasanur Forest disease with its vector.
Kyasanur Forest disease, also called monkey fever, is a viral illness spread by the hard tick Haemaphysalis spinigera in forest areas of Karnataka. So Kyasanur Forest disease pairs with Hard tick, item 4.

Step 5: Put the pairs together and check the codes.
The full match is A-3, B-2, C-1, D-4. Checking the four coded options, this exact combination is given in the first option.

Step 6: Final answer.
\[ \boxed{\text{A-3, B-2, C-1, D-4}} \]
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