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locus of the point of intersection of perpendicula
Question:
Locus of the point of intersection of perpendicular tangents to the circle
$x^2 + y^2 = 16 $
is
Updated On:
Jul 6, 2022
$x^2 + y^2 = 8 $
$x^2 + y^2 = 32 $
$ x^2 + y^2 = 64$
$x^2 + y^2 = 16. $
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The Correct Option is
B
Solution and Explanation
Answer (b)
$x^2 + y^2 = 32 $
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