Question

LIST-I contains compounds and LIST-II contains reaction
 

LIST-I		LIST-II
I	\(\text{H}_2\text{O}_2\)	P	\(\text{Mg(HCO}_3\text{)}_2 + \text{Ca(OH)}_2 \rightarrow \)
II	\(\mathrm{Mg(OH)_2}\)	Q	\(\text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \)
III	\(\text{BaCl}_2\)	R	\(\text{Ca(OH)}_2 + \text{MgCl}_2 \)
IV	\(\text{CaCO}_3\)	S	\(\text{BaO}_2 + 2\text{HCl} \rightarrow\)
		T	\(\text{Ca(HCO}_3\text{)}_2 + 2\text{Ca(OH)}_2 \rightarrow \)

Match each compound in LIST – I with its formation reaction(s) in LIST-II, and choose the correct option

• A. I → Q; II → P; III → S; IV → R
• B. I → T; II → P; III → Q; IV → R
• C. I → T; II → R; III → Q; IV → P
• D. I → Q; II → R; III → S; IV → P

Answer 1

The Correct Option is D

1. \( \text{H}_2\text{O}_2 \) (Compound I):

The formation of hydrogen peroxide (\( \text{H}_2\text{O}_2 \)) happens by the reaction between \( \text{BaO}_2 \) and \( \text{H}_2\text{SO}_4 \).
This corresponds to reaction Q.

2. \( \text{Mg(OH)}_2 \) (Compound II):

The formation of magnesium hydroxide (\( \text{Mg(OH)}_2 \)) occurs when \( \text{Ca(OH)}_2 \) reacts with \( \text{MgCl}_2 \). 
This corresponds to reaction R.

3. \( \text{BaCl}_2 \) (Compound III):

Barium chloride (\( \text{BaCl}_2 \)) reacts with hydrochloric acid to form barium peroxide (\( \text{BaO}_2 \)), which corresponds to reaction S.

4. \( \text{CaCO}_3 \) (Compound IV):

Calcium carbonate (\( \text{CaCO}_3 \)) is formed when \( \text{Mg(HCO}_3\text{)}_2 \) reacts with \( \text{Ca(OH)}_2 \), corresponding to reaction P.

Final Answer:

The correct matches are:

• I → Q: \( \text{H}_2\text{O}_2 \) formation
• II → R: \( \text{Mg(OH)}_2 \) formation
• III → S: \( \text{BaCl}_2 \) formation
• IV → P: \( \text{CaCO}_3 \) formation

Correct Option:

The correct option is A: I → Q; II → R; III → S; IV → P.