We are tasked with finding the minimum distance between two circles, \( C_1 \) and \( C_2 \), given their centers and radii. Let us proceed step by step:
1. Given Information:
The centers and radii of the circles are:
\( C_1(8, 2), \quad r_1 = 1 \)
\( C_2(2, 6), \quad r_2 = 2 \)
2. Distance Between the Centers:
The distance between the centers \( C_1 \) and \( C_2 \) is given by the Euclidean distance formula:
\( C_1C_2 = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)
3. Minimum Distance Between the Circles:
The minimum distance between the two circles is the distance between their centers minus the sum of their radii:
\( |z_1 - z_2| = C_1C_2 - (r_1 + r_2) \)
Substitute \( C_1C_2 = 10 \), \( r_1 = 1 \), and \( r_2 = 2 \):
\( |z_1 - z_2| = 10 - (1 + 2) \)
\( |z_1 - z_2| = 10 - 3 = 7 \)
Final Answer:
The minimum distance between the two circles is \( \boxed{7} \).
In the figure, triangle ABC is equilateral. 
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]