Step 1: Recall the definition of correlation (covariance) between two random variables.
For two random variables \(U\) and \(V\), the correlation used here is the covariance
\[
\text{Corr}(U,V)=E[UV]-E[U]E[V]
\]
Step 2: Note the basic facts about X and N.
\(X\) is uniform on \([-1,1]\), so
\[
E[X]=0,\qquad \text{Var}(X)=\frac{(1-(-1))^2}{12}=\frac{4}{12}=\frac{1}{3}
\]
Because the density of \(X\) is symmetric about \(0\), every odd moment of \(X\) is zero, so
\[
E[X^3]=0
\]
\(N\) has zero mean, and \(X\), \(N\) are independent, so
\[
E[XN]=E[X]E[N]=0,\qquad E[X^2N]=E[X^2]E[N]=0
\]
Step 3: Find the correlation between X and Y.
\[
\text{Corr}(X,Y)=E[XY]-E[X]E[Y]=E[X(X+N)]-0=E[X^2]+E[XN]
\]
Since \(E[X]=0\), \(E[X^2]=\text{Var}(X)=\frac{1}{3}\), and \(E[XN]=0\):
\[
\text{Corr}(X,Y)=\frac{1}{3}+0=\frac{1}{3}
\]
Step 4: Find the correlation between X and Z.
\[
\text{Corr}(X,Z)=E[XZ]-E[X]E[Z]=E[X(X^2+N)]-0=E[X^3]+E[XN]
\]
Since \(E[X^3]=0\) (odd moment of a symmetric distribution) and \(E[XN]=0\) (independence):
\[
\text{Corr}(X,Z)=0+0=0
\]
Step 5: Analyze the options.
(A) 1/3 and 0: Matches both computed values exactly. Correct.
(B) 1/3 and 1/9: The first value is right but the second should be \(0\), not \(\frac{1}{9}\), since the odd moment \(E[X^3]\) vanishes. Incorrect.
(C) 1/3 and 1/3: Would only hold if \(E[X^3]\) equalled \(\frac{1}{3}\), but it is zero by symmetry. Incorrect.
(D) 1 and 0: The correlation between X and Y is \(\text{Var}(X)=\frac{1}{3}\), not \(1\), since \(X\) does not have unit variance. Incorrect.
Step 6: Final conclusion.
Therefore, the required pair of correlation values is
\[
\boxed{\frac{1}{3}\text{ and }0}
\]