The function \( f(x) = [x] + |x - 2| \) consists of two components:
1. The greatest integer function, \( [x] \), which has discontinuities at integer values of \( x \).
2. The absolute value function, \( |x - 2| \), which has a critical point at \( x = 2 \).
Now, consider the interval \( -2<x<3 \). The points where \( f(x) \) is not continuous or differentiable are determined by:
- Discontinuities in \( [x] \), which happen at \( x = -1, 0, 1, 2 \).
- A critical point in \( |x - 2| \) at \( x = 2 \).
So, the points where \( f(x) \) is not continuous are \( x = -1, 0, 1, 2 \), which gives us \( m = 4 \) discontinuities. The points where \( f(x) \) is not differentiable are due to the change in the slope at these points. Specifically, the function is not differentiable at \( x = 2 \), so \( n = 1 \).
Thus, \( m + n = 4 + 3 = 7 \).
Final Answer: \( m + n = 7 \).
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]