It is provided that,
\(P(X = 3) = 5P(X = 4) \;and \;n = 7\)
\(⇒ ^7C_3p^3q^4 = 5⋅^7C_4p^4q^3\)
\(⇒ q = 5p\) and also \(p + q = 1\)
\(⇒p=\frac{1}{6}\) and \(q=\frac{5}{6}\)
So, Mean =\(\frac{7}{6}\) and variance =\(\frac{35}{36}\)
Therefore, \(Mean + Variance\) = \(\frac{7}{6}+\frac{35}{36}\)
= \(\frac{77}{36}\)
Hence, the correct option is (C): \(\frac{77}{36}\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
A random variable is a variable whose value is unknown or a function that assigns values to each of an experiment's results. Random variables are often deputed by letters and can be classified as discrete, which are variables that have particular values, or continuous, which are variables that can have any values within a continuous range.
Random variables are often used in econometric or regression analysis to ascertain statistical relationships among one another.
There are two types of random variables, such as: