Step 1: Find the power function.
Since
\[
X\sim U(0,\theta),
\]
the density function is
\[
f(x)=\frac{1}{\theta}, \qquad 0<x<\theta
\]
The critical region is
\[
X<\frac34
\]
Hence, the power function is
\[
\beta(\theta)
=
P_\theta\left(X<\frac34\right)
\]
For a uniform distribution,
\[
P_\theta(X<a)=
\begin{cases}
\dfrac{a}{\theta}, & a<\theta,\\
1, & a\geq \theta.
\end{cases}
\]
Taking
\[
a=\frac34,
\]
we get
\[
\beta(\theta)=
\begin{cases}
1, & 0<\theta\leq \dfrac34,\\
\dfrac{3}{4\theta}, & \theta>\dfrac34.
\end{cases}
\]
Step 2: Check option (A).
The size of the test is
\[
\sup_{\theta\geq 1}\beta(\theta)
\]
For
\[
\theta\geq 1,
\]
we use
\[
\beta(\theta)=\frac{3}{4\theta}
\]
This function decreases as \(\theta\) increases. Hence, the supremum occurs at
\[
\theta=1
\]
Therefore,
\[
\text{Size}=\beta(1)=\frac34
\]
So, option (A) is true.
Step 3: Check option (B).
For
\[
\theta<1,
\]
the power function is
\[
\beta(\theta)=
\begin{cases}
1, & 0<\theta\leq \dfrac34,\\
\dfrac{3}{4\theta}, & \dfrac34<\theta<1.
\end{cases}
\]
Now,
\[
\frac{3}{4\theta}
\]
decreases as \(\theta\to 1^{-}\).
Thus,
\[
\inf_{\theta<1}\beta(\theta)
=
\lim_{\theta\to 1^-}\frac{3}{4\theta}
=
\frac34
\]
Hence, option (B) is true.
Step 4: Check option (C).
If
\[
0<\theta\leq \frac34,
\]
then
\[
\beta(\theta)=1
\]
Thus, it is not true that
\[
\beta(\theta)<1
\]
for all \(\theta>0\).
Hence, option (C) is NOT true.
Step 5: Check option (D).
As
\[
\theta\to 0,
\]
eventually
\[
\theta<\frac34
\]
and therefore
\[
\beta(\theta)=1
\]
Hence,
\[
\lim_{\theta\to 0}\beta(\theta)=1
\]
So, option (D) is true.
Step 6: Final conclusion.
The statement which is NOT true is
\[
\boxed{(C)}
\]