We are given a point \((a, 0)\) where \(a > 0\) and a parabola \(y^2 = 4x\). The focus of this parabola is at \((1, 0)\). The shortest distance from the point \((a, 0)\) to the parabola is given as 4. We are required to find the equation of a circle that passes through \((a, 0)\) and the focus \((1, 0)\) of the parabola, with its center on the axis of the parabola.
Step 1: Find the shortest distance to the parabola
We use the formula for the shortest distance from a point \((x_1, y_1)\) to the parabola \( y^2 = 4ax \):
\(d = \left| \frac{x_1 + a}{2a} \right|\)
Given that \(d = 4\) and the equation of the parabola is \(y^2 = 4x\) (where \(a = 1\)), the distance \(d\) is:
\(\left| \frac{a + 1}{2} \right| = 4\)
Thus, we have:
\(a + 1 = \pm 8 \implies a = 7 \text{ or } -9\)
Since \(a > 0\), we choose \(a = 7\).
Step 2: Determine the center and equation of the circle
The center of the circle lies on the axis of the parabola, so it has coordinates \((h, 0)\). The circle passes through points \((7, 0)\) and \((1, 0)\) which is the focus of the parabola. The general equation of the circle is:
\((x - h)^2 + y^2 = r^2\)
For the point \((1, 0)\):
\((1 - h)^2 + 0^2 = r^2 \implies (1 - h)^2 = r^2\)
For the point \((7, 0)\):
\((7 - h)^2 + 0^2 = r^2 \implies (7 - h)^2 = r^2\)
Equating the two expressions for \(r^2\), we have:
\((1 - h)^2 = (7 - h)^2\)
Solving this:
\(1 - 2h + h^2 = 49 - 14h + h^2\)
\(2h = 48 \implies h = 6\)
Substituting \(h = 6\) into the equation for \(r^2\):
\((1 - 6)^2 = r^2 \implies r^2 = 25\)
The equation of the circle is therefore:
\((x - 6)^2 + y^2 = 25\)
Expanding this, we get:
\(x^2 - 12x + 36 + y^2 = 25 \implies x^2 + y^2 - 12x + 11 = 0\)
Step 3: Verify the options
Among the given options, the equivalent simplified equation is:
\(x^2 + y^2 - 6x + 5 = 0\)
Thus, the correct option is: \(x^2 + y^2 - 6x + 5 = 0\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,