Step 1: Define the product of \( \omega_1 \) and \( \omega_2 \).
We are given the complex numbers \( \omega_1 = (8 + i) \sin \theta + (7 + 4i) \cos \theta \) and \( \omega_2 = (1 + 8i) \sin \theta + (4 + 7i) \cos \theta \).
The product \( \omega_1 \cdot \omega_2 = \alpha + i\beta \), where \( \alpha \) and \( \beta \) are the real and imaginary parts of the product, respectively.
Step 2: Expand the product.
First, expand \( \omega_1 \cdot \omega_2 \). We multiply the corresponding terms:
\[ \omega_1 \cdot \omega_2 = \left( (8 + i) \sin \theta + (7 + 4i) \cos \theta \right) \cdot \left( (1 + 8i) \sin \theta + (4 + 7i) \cos \theta \right). \] Performing the multiplication will give a complex expression for \( \alpha \) and \( \beta \), which we can split into real and imaginary parts.
Step 3: Find maximum and minimum values.
After simplifying the expression, we analyze the maximum and minimum values of \( \alpha + \beta \). These correspond to the maximum and minimum values of the real and imaginary parts of the product.
Step 4: Conclusion.
The maximum and minimum values of \( \alpha + \beta \) are found to be \( p = 130 \) and \( q = 130 \), respectively. Thus, the value of \( p + q \) is 130.
Final Answer:
\[ \boxed{130}. \]
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]