The correct answer is 37
There are 16 ordered pairs in S × S. We write all these ordered pairs in 4 sets as follows.
A = {(1, 1)}
B = {(1, 4), (2, 4), (3, 4) (4, 4), (4, 3), (4, 2), (4, 1)}
C = {(1, 3), (2, 3), (3, 3), (3, 2), (3, 1)}
D = {(1, 2), (2, 2), (2, 1)}
All elements of set B have image 4 and only element of A has image 1.
All elements of set C have image 3 or 4 and all elements of set D have image 2 or 3 or 4.
We will solve this question in two cases.
Case I : When no element of set C has image 3.
Number of onto functions = 2 (when elements of set D have images 2 or 3)
Case II : When atleast one element of set C has image 3.
Number of onto functions = (23 – 1)(1 + 2 + 2) = 35
Therefore , total number of functions = 37
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}
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