Step 1: Understand the relation.
The relation is given by:
\[
x+2y=8,
\]
where
\[
x,y\in N.
\]
Step 2: Express \(x\) in terms of \(y\).
\[
x=8-2y.
\]
Step 3: Use natural number values of \(y\).
Since \(y\in N\), take positive natural values:
\[
y=1,2,3,\ldots
\]
Step 4: Find corresponding values of \(x\).
For \(y=1\):
\[
x=8-2(1)=6.
\]
For \(y=2\):
\[
x=8-2(2)=4.
\]
For \(y=3\):
\[
x=8-2(3)=2.
\]
Step 5: Check next value.
For \(y=4\):
\[
x=8-2(4)=0.
\]
But \(0\) is not included in natural numbers here.
Step 6: Write valid \(x\)-values.
Valid values of \(x\) are:
\[
6,\ 4,\ 2.
\]
So, the domain is:
\[
\{2,4,6\}.
\]
Step 7: Final conclusion.
Thus, the domain of relation \(R\) is:
\[
\boxed{\{2,4,6\}}.
\]