Question

Let f : Z→ \(Z_2\), be a homomorphism of groups defined by
\(f(a) =   \begin{cases}    0,  & \quad \text{if } a \text{ is even}\\     1,  & \quad \text{if } a \text{ is odd}   \end{cases}\)

then Kerf is : 

• A. The set of all odd integers
• B. The set of all even integers
• C. The set of all natural numbers
• D. The set of all real numbers

Answer 1

The Correct Option is B

The correct option is(B):The set of all even integers