Let $ f(x) = a + \left( (x - 4) \right)^4 / 9 $, $\text{ then minima of } $ f(x) $\text{ is} $
To analyze the function \( f(x) = a + (x - 4)^{4/9} \) and determine its extremum:
1. Compute the Derivative:
We first find the derivative of \( f(x) \):
\[ f'(x) = \frac{d}{dx}\left[a + (x - 4)^{4/9}\right] = \frac{4}{9}(x - 4)^{-5/9} \]
2. Identify Critical Points:
The derivative is undefined when the denominator becomes zero:
\[ (x - 4)^{-5/9} = \frac{1}{(x - 4)^{5/9}} \Rightarrow \text{undefined at } x = 4 \]
Thus, \( x = 4 \) is a critical point where the derivative does not exist.
3. Determine Extremum at Critical Point:
Evaluating the function at \( x = 4 \):
\[ f(4) = a + (4 - 4)^{4/9} = a + 0 = a \]
Since the function has a well-defined value here while its derivative is undefined, this represents a point of extremum.
4. Verify Minimum Value:
For all \( x \neq 4 \):
\[ (x - 4)^{4/9} > 0 \Rightarrow f(x) = a + \text{positive term} > a \]
Therefore, \( f(4) = a \) is indeed the minimum value of the function.
Final Answer:
The function \( f(x) \) has its minimum value at \( x = 4 \), which is \( a \).
If $ f(x) = \begin{cases} x, & 0 \leq x \leq 1 \\ 2x - 1, & x > 1 \end{cases} $, then: