The function f is discontinuous exactly at the point in (0,1)
There is exactly one point in (0,1) at which the function f is continuous but not differentiable
the function f is not differentiable at more than three points in (0,1)
The minimum value of the function f is\(-\frac{1}{512}\)
To analyze the function \( f(x) = [4x](x-\frac{1}{4})^2(x-\frac{1}{2}) \), where \( [x] \) denotes the greatest integer less than or equal to \( x \), follow these steps:
1. Check where \( [4x] \) may change value within \( (0,1) \). Notice \( [4x]=n \) where \( n \) is an integer, specifically \( n \in \{1, 2, 3\} \) because \( 0 < 4x < 4 \).
2. Points where changes occur are \( x = \frac{1}{4}, \frac{1}{2}, \frac{3}{4} \). Evaluate continuity at these points:
3. Therefore, \( f \) is not continuous at these three points.
1. The problem asks to find exactly one point where the function is continuous but not differentiable:
Thus, function \( f \) is continuous at this domain but not differentiable.
Let \(f(x)=x+log_{e}x−xlog_{e}x,\text{ }x∈(0,∞)\).