Question:
Let A = {x, y, z, u} and B = {a, b}. A function f : A → B is selected randomly. The probability that the function is an onto function is
Let A = {x, y, z, u} and B = {a, b}. A function f : A → B is selected randomly. The probability that the function is an onto function is
Show Hint
When calculating the probability of selecting an onto function, use the principle of inclusion-exclusion. First, calculate the total number of functions, then subtract the cases where the function is not onto, and finally divide by the total number of functions to find the probability.
Updated On: Apr 6, 2025
- \(\frac{5}{8}\)
- \(\frac{7}{8}\)
- \(\frac{1}{35}\)
- \(\frac{1}{8}\)
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Was this answer helpful?
3
13
Top Questions on Probability
- If $F$ is an event of a sample space $S$, then $P(S|F)=$
- If $A$ and $B$ are independent events with $P(A)=0.3$ and $P(B)=0.4$, then $P(A \cap B)$ is
- The probability of obtaining an even prime number on each die when a pair of dice is rolled is
- A box contains 5 red and 7 white balls. Two balls are drawn at random. What is the probability that both are red?
- If \( \alpha \) and \( \beta \) (\( \alpha<\beta \)) are the roots of the equation \( (-2 + \sqrt{3})(\sqrt{x} - 3) + (x - 6\sqrt{x}) + (9 - 2\sqrt{3}) = 0 \), \( x \ge 0 \), then \( \sqrt{\frac{\beta}{\alpha}} + \sqrt{\alpha\beta} \) is equal to:
- JEE Main - 2026
- Mathematics
- Probability
View More Questions
Questions Asked in KCET exam
Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \).
Choose the correct answer from the options given below:- KCET - 2025
- Differentiability
- If \[ y = \frac{\cos x}{1 + \sin x} \] then:
- KCET - 2025
- Differentiability
- A function \( f(x) \) is given by:
\[ f(x) = \begin{cases} \frac{1}{e^x - 1}, & \text{if } x \neq 0 \\ \frac{1}{e^x + 1}, & \text{if } x = 0 \end{cases} \] Then, which of the following is true?- KCET - 2025
- Limits
- The function f(x) is given by:
For x < 0:
f(x) = ex + axFor x ≥ 0:
f(x) = b(x - 1)2
The function is differentiable at x = 0. Then,- KCET - 2025
- Differentiability
- The function \( f(x) = \tan x - x \)
- KCET - 2025
- Derivatives
View More Questions