To solve this problem, we need to analyze the given information about the vertices and circumcentre of ΔABC.
The vertices of ΔABC are A(α, -2), B(α, 6), and C(\(<\alpha/4\), -2). The circumcentre is given as (5, \(\alpha/4\)).
The circumcentre of a triangle is equidistant from all the vertices. Hence, we have the following equations for the circumradius (R), considering the point (5, \(\alpha/4\)) as the circumcentre:
Equating any two distances will give us the value of α. Solving these equations will lead us to α = 4.
The perimeter option stating "Perimeter is 25" is incorrect because the calculated perimeter is 16.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
In all cases, horizontal lines remain parallel to the x-axis. It never intersects the x-axis but only intersects the y-axis. The value of x can change, but y always tends to be constant for horizontal lines.

The equation for the vertical line is represented as x=a,
Here, ‘a’ is the point where this line intersects the x-axis.
x is the respective coordinates of any point lying on the line, this represents that the equation is not dependent on y.

⇒ Horizontal lines and vertical lines are perpendicular to each other.