Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ mol\(-1\), and 4 kJ mol\(-1\), respectively.
The hydration enthalpy of NaCl is :
The hydration enthalpy of NaCl is :
Show Hint
- \(-780\) kJ mol\(-1\)
- \(-784\) kJ mol\(-1\)
- 780 kJ mol\(-1\)
- 784 kJ mol\(-1\)
The Correct Option is B
Solution and Explanation
\(\Delta H_{sol} = \Delta H_{lattice} + \Delta H_{hyd}\)
\(4 = 788 + \Delta H_{hyd}\)
\(\Delta H_{hyd} = 4 - 788 = -784\) kJ mol\(-1\)
Answer: (2) \(-784\) kJ mol\(-1\)
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