Question:

Larger number of oxidation states are exhibited by the actinoids than those of lanthanoids. The reason is:

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The larger number of oxidation states in actinoids is due to the relatively smaller energy difference between the 5f and 6d orbitals, allowing for more flexibility in electron configuration.
Updated On: May 5, 2026
  • Lesser energy difference between 5f and 6d than between 4f and 5d orbitals
  • More energy difference between 5f and 6d than between 4f and 5d orbitals
  • 4f orbitals are more diffused than 5f orbitals
  • Highly reactive nature of the actinoids
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The Correct Option is A

Solution and Explanation

Step 1: Consider the electronic configurations of lanthanoids and actinoids.
Lanthanoids and actinoids both belong to the f-block elements, where the f-orbitals play a crucial role in determining the oxidation states. The lanthanoids have their electrons filling the 4f orbitals, while the actinoids have their electrons filling the 5f orbitals.

Step 2: Compare the energy levels of f and d orbitals.

- In the actinoids, the 5f orbitals are closer in energy to the 6d orbitals. This allows actinoids to easily exhibit a greater variety of oxidation states because electrons from both the f and d orbitals can be involved in bonding.
- In contrast, the 4f orbitals in lanthanoids are more tightly bound and more separated from the 5d orbitals, limiting the number of oxidation states they can exhibit.

Step 3: Conclusion.

Thus, the smaller energy difference between the 5f and 6d orbitals in the actinoids allows them to exhibit a larger number of oxidation states compared to the lanthanoids. This makes option (A) the correct answer.
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