Question:
K$_{sp}$ of Mg(OH)$_2$ is \(1\times10^{-12}\).
0.01 M MgCl$_2$ solution will precipitate when limiting pH is
K$_{sp}$ of Mg(OH)$_2$ is \(1\times10^{-12}\).
0.01 M MgCl$_2$ solution will precipitate when limiting pH is
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Use solubility product comparison with ionic product.
Updated On: Jan 9, 2026
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The Correct Option is C
Solution and Explanation
Step 1: Ionic product \[ IP=[Mg^{2+}][OH^-]^2. \]
Step 2: Precipitation when \(IP>1\times10^{-12}\). Given \([Mg^{2+}]=0.01\). \[ [OH^-]^2>1\times10^{-10} \Rightarrow[OH^-]>1\times10^{-5}. \]
Step 3: \[ pOH<5 \Rightarrow pH>9. \] Nearest option 10.
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