Step 1: Understanding the Concept:
The stability of alkenes is primarily determined by the degree of substitution at the double bond. According to Saytzeff's rule and hyperconjugation, more substituted alkenes are generally more stable.
Step 2: Detailed Explanation:
Stability increases with the number of $\alpha$-hydrogens (hyperconjugative structures).
C. 2,3-Dimethylbut-2-ene: $(CH_3)_2C=C(CH_3)_2$. It is tetra-substituted and has 12 $\alpha$-H. (Most stable).
A. 2-Methylbut-2-ene: $(CH_3)_2C=CHCH_3$. It is tri-substituted and has 9 $\alpha$-H.
B. cis-But-2-ene: $CH_3CH=CHCH_3$. It is di-substituted and has 6 $\alpha$-H.
D. Prop-1-ene: $CH_3CH=CH_2$. It is mono-substituted and has 3 $\alpha$-H. (Least stable).
Order: C >A >B >D.
Step 3: Final Answer:
The stability order is C >A >B >D.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,