Step 1: Understanding the Concept:
The stability of alkenes is primarily determined by the degree of substitution at the double bond. According to Saytzeff's rule and hyperconjugation, more substituted alkenes are generally more stable.
Step 2: Detailed Explanation:
Stability increases with the number of $\alpha$-hydrogens (hyperconjugative structures).
C. 2,3-Dimethylbut-2-ene: $(CH_3)_2C=C(CH_3)_2$. It is tetra-substituted and has 12 $\alpha$-H. (Most stable).
A. 2-Methylbut-2-ene: $(CH_3)_2C=CHCH_3$. It is tri-substituted and has 9 $\alpha$-H.
B. cis-But-2-ene: $CH_3CH=CHCH_3$. It is di-substituted and has 6 $\alpha$-H.
D. Prop-1-ene: $CH_3CH=CH_2$. It is mono-substituted and has 3 $\alpha$-H. (Least stable).
Order: C >A >B >D.
Step 3: Final Answer:
The stability order is C >A >B >D.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)