Step 1: Understanding the Concept:
The question asks whether the standard deviation (SD) of a set of 20 measurements is less than 3. This is a ""Yes/No"" question. A statement is sufficient if it allows us to answer with a definitive ""Yes"" or a definitive ""No"".
Step 2: Key Formula or Approach:
The relationship between standard deviation and variance is fundamental: \[ \text{Standard Deviation} = \sqrt{\text{Variance}} \] The variance is the average of the squared differences from the mean (\(\mu\)): \[ \text{Variance} = \frac{1}{N} \sum_{i=1}^{N} (x_i - \mu)^2 \] Step 3: Detailed Explanation:
The question is: Is SD \(< 3\)?
Analyze Statement (1): The variance for the set of measurements is 4.
Using the formula, we can calculate the standard deviation: \[ \text{SD} = \sqrt{\text{Variance}} = \sqrt{4} = 2 \] Now we can answer the question: Is \(2<3\)? Yes. Since we get a definitive ""Yes"", statement (1) is sufficient.
Analyze Statement (2): For each measurement, the difference between the mean and that measurement is 2.
This means that for every \(x_i\) in the set, the absolute difference \(|x_i - \mu|\) is 2.
This implies that the squared difference \((x_i - \mu)^2\) is \(2^2 = 4\) for every measurement.
Now we can calculate the variance for the 20 measurements (\(N=20\)): \[ \text{Variance} = \frac{1}{20} \sum_{i=1}^{20} (x_i - \mu)^2 = \frac{1}{20} \sum_{i=1}^{20} 4 \] \[ \text{Variance} = \frac{1}{20} (20 \times 4) = 4 \] With the variance being 4, we can find the standard deviation: \[ \text{SD} = \sqrt{4} = 2 \] Again, we can answer the question: Is \(2<3\)? Yes. Since we get a definitive ""Yes"", statement (2) is sufficient.
Step 4: Final Answer:
Both statements, independently, provide enough information to definitively answer the question.