Question:
\[
\int_{-\pi/2}^{\pi/2} |\sin x| dx \text{ equals to}
\]
\[
\int_{-\pi/2}^{\pi/2} |\sin x| dx \text{ equals to}
\]
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The Lande interval rule determines energy level separations in multiplets.
Updated On: Dec 11, 2025
- 0
- 1
- -1
- 2
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The Correct Option is D
Solution and Explanation
\(|\sin x|\) is an even function, symmetric about y-axis. \[ \int_{-\pi/2}^{\pi/2} |\sin x| dx = 2 \int_0^{\pi/2} \sin x dx = 2 [-\cos x]_0^{\pi/2} = 2 (0 + 1) = 2 \]
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