To inhibit the growth of tumours, identify the compounds used from the following:
(A) EDTA
(B) Coordination Compounds of Pt
(C) D – Penicillamine
(D) Cis – Platin
Choose the correct answer from the options given below:
Cisplatin and other platinum-based coordination compounds are effective anticancer drugs. They form cross-links with DNA, disrupting cell division and leading to tumour inhibition.
B and D Only
C and D Only
A and B Only
A and C Only
Step 1: Role of Coordination Compounds of Platinum
- Platinum-based coordination compounds, such as Cisplatin (\(\text{cis-}[\text{Pt}(\text{NH}_3)_2\text{Cl}_2]\)), are widely used in chemotherapy.
- These compounds inhibit tumour growth by binding to DNA and interfering with the replication process.
Step 2: Analysis of the Options
Option A (EDTA): EDTA is primarily a chelating agent used for metal ion sequestration, not for tumour treatment.
Option B (Coordination Compounds of Pt): Correct, as platinum-based compounds are effective in tumour inhibition.
Option C (D -- Penicillamine): Penicillamine is used in chelation therapy for heavy metal poisoning, not for tumours.
Option D (Cisplatin): Correct, as it is a well-known platinum-based anti-cancer drug.
Conclusion: The correct combination is B and D. Therefore, the correct answer is (1) B and D Only.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,